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Might I suggest that you go to your Goldsmith with your ideas,minus the
idea of *supplying* the needed Gold in the form of Krugerrands, determining a cost and using those coins as the method of payment? Krugerrands have both an intrinsic value and a market value. The market value is generally higher than their intrinsic ( Gold content ) value. This way you will not be insulting the Goldsmith with your implication that he is the biggest thief in the country. And you will find that your ring will cost more than just Gold price in any event. In fact it may take 3 of your coins to pay for a ring weighing less than the Gold content of just one of them. Do yourself a favor. Stop insulting the integrity of people more likely to be SCRUPULOUSLY honest, honest to a fault even, than you yourself are in your everyday dealings. -- Don Thompson Ex ROMAD "Jeff S. " wrote in message ... I am going to have a jeweller custom make a 14k gold signet ring for me soon. The gold he'll be using will be supplied by me in the form of either one or two 1/4 oz., 24 karat solid gold Kuggerand coins. Of course what he'll do is make a wax model, weight it, and then tell me how much 24 K gold he's going to need for the ring, taking into account that he'll be adding metals to it to bring it down to 14 karats. What I need to know, to make sure I'm not getting ripped off, is how many ounces (or grams or pennyweight) of 14 K gold will a 24 K ounce of gold yield? In other words, if he hypothetically says the ring will weigh 1/8 ounce at 14 K, then how much 24 K gold will he need to make the ring? Can it be stated that 1 ounce of 24 K gold will yield X ounces of 14 K gold? While I do my best to deal with my IP's newsgroup service, on occasion I do not get to check the groups to see replies to my postings for the mere nanosecond they're actually left up on the server. So please also send an e mail copy of your answer to me at . Remove the X's before sending. Thanks much, Jeff |
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